求个多字符匹配（英文）

V2EX = way to explore

V2EX 是一个关于分享和探索的地方

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GET /ecx/ HTTP/1.1
Host: test.baidu.com
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:35.0) Gecko/20100101 Firefox/35.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,/;q=0.8
Accept-Language: zh-cn,zh;q=0.8,en-us;q=0.5,en;q=0.3
Accept-Encoding: gzip, deflate
Cookie: __utma=89925662.1398539168.1423185721.1423185721.1423185721.1; __utmz=89925662.1423185721.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none)
Connection: keep-alive

求个正则匹配 GET或者POST后面的地址(例如/ecx/)和Host后面的地址(例如test.baidu.com)
谢

q=0.8

Direct

wow64

1 replies • 2015-02-09 15:38:27 +08:00

lapertem4

Feb 9, 2015

s = re.findall(r'^(POST|GET)(.*)HTTP',cont,re.M)
q = re.findall(r'^Host:(.*)',cont,re.M)

if s and q:
print s[0][1].strip()
print q[0].strip()