推荐学习书目
› Learn Python the Hard Way
Python Sites
› PyPI - Python Package Index
› http://diveintopython.org/toc/index.html
› Pocoo
值得关注的项目
› PyPy
› Celery
› Jinja2
› Read the Docs
› gevent
› pyenv
› virtualenv
› Stackless Python
› Beautiful Soup
› 结巴中文分词
› Green Unicorn
› Sentry
› Shovel
› Pyflakes
› pytest
Python 编程
› pep8 Checker
Styles
› PEP 8
› Google Python Style Guide
› Code Style from The Hitchhiker's Guide
这是一个创建于 2244 天前的主题，其中的信息可能已经有所发展或是发生改变。
[b"['2018-10-11 08:16:00', 6498, 6525, 6497.5, 6503.5, 1539216960000]", b"['2018-10-11 08:17:00', 6503.5, 6523.5, 6497.5, 6514.5, 1539217020000]", b"['2018-10-11 08:18:00', 6514.5, 6515, 6490.5, 6492, 1539217080000]", b"['2018-10-11 08:19:00', 6492, 6495, 6490, 6490, 1539217140000]",]
我从 redis 取出的数据是这样 要怎么将他转换为嵌套列表呢，这个 b 要怎么去掉呢
4 条回复 • 2018-10-13 00:07:43 +08:00
 |
1
enenaaa 2018-10-11 14:45:37 +08:00
b 说明是二进制串。 转成 unicode 后， 按 json 解析。
|
 |
2
locoz 2018-10-11 14:49:11 +08:00
[json.loads(i.decode().replace("'", '"')) for i in a]
|
 |
3
ltoddy 2018-10-11 20:40:18 +08:00
```
>>> d = [b"['2018-10-11 08:16:00', 6498, 6525, 6497.5, 6503.5, 1539216960000]", b"['2018-10-11 08:17:00', 6503.5, 6523.5, 6497.5, 6514.5, 1539217020000]", b"['2018-10-11 08:18:00', 6514.5, 6515, 6490.5, 6492, 1539217080000]", b"['2018-10-11 08:19:00', 6492, 6495, 6490, 6490, 1539217140000]",] >>> >>> >>> >>> [s.decode() for s in d] ["['2018-10-11 08:16:00', 6498, 6525, 6497.5, 6503.5, 1539216960000]", "['2018-10-11 08:17:00', 6503.5, 6523.5, 6497.5, 6514.5, 1539217020000]", "['2018-10-11 08:18:00', 6514.5, 6515, 6490.5, 6492, 1539217080000]", "['2018-10-11 08:19:00', 6492, 6495, 6490, 6490, 1539217140000]"] >>> ``` |
 |
4
datou 2018-10-13 00:07:43 +08:00
redis 读数据库的时候有个参数是编码成字符串
|
Select Language