[求助] 如何简化Switch代码

[darktiny]

需要根据天气Code获取相应图片资源的ID，如何有效地简化？谢谢

/**
* Stupid Code!!!
*
* @param code
* @return
*/
private int getResourceId(int code) {
int resId = 0;
switch (code) {
case 3:
resId = R.drawable.ic_weather_3;
break;
case 4:
resId = R.drawable.ic_weather_4;
break;
case 5:
resId = R.drawable.ic_weather_5;
break;
case 6:
resId = R.drawable.ic_weather_6;
break;
case 7:
resId = R.drawable.ic_weather_7;
break;
case 8:
resId = R.drawable.ic_weather_8;
break;
case 9:
resId = R.drawable.ic_weather_9;
break;
case 10:
resId = R.drawable.ic_weather_10;
break;
case 11:
resId = R.drawable.ic_weather_11;
break;
case 12:
resId = R.drawable.ic_weather_12;
break;
case 13:
resId = R.drawable.ic_weather_13;
break;
case 14:
resId = R.drawable.ic_weather_14;
break;
case 15:
resId = R.drawable.ic_weather_15;
break;
case 16:
resId = R.drawable.ic_weather_16;
break;
case 17:
resId = R.drawable.ic_weather_17;
break;
case 18:
resId = R.drawable.ic_weather_18;
break;
case 19:
resId = R.drawable.ic_weather_19;
break;
case 20:
resId = R.drawable.ic_weather_20;
break;
case 21:
resId = R.drawable.ic_weather_21;
break;
case 22:
resId = R.drawable.ic_weather_22;
break;
case 23:
resId = R.drawable.ic_weather_23;
break;
case 26:
resId = R.drawable.ic_weather_26;
break;
case 27:
resId = R.drawable.ic_weather_27;
break;
case 28:
resId = R.drawable.ic_weather_28;
break;
case 29:
resId = R.drawable.ic_weather_29;
break;
case 30:
resId = R.drawable.ic_weather_30;
break;
case 31:
resId = R.drawable.ic_weather_31;
break;
case 32:
resId = R.drawable.ic_weather_32;
break;
case 33:
resId = R.drawable.ic_weather_33;
break;
case 34:
resId = R.drawable.ic_weather_34;
break;
case 35:
resId = R.drawable.ic_weather_35;
break;
case 36:
resId = R.drawable.ic_weather_36;
break;
case 37:
resId = R.drawable.ic_weather_37;
break;
case 38:
resId = R.drawable.ic_weather_38;
break;
case 39:
resId = R.drawable.ic_weather_39;
break;
case 40:
resId = R.drawable.ic_weather_40;
break;
case 41:
resId = R.drawable.ic_weather_41;
break;
case 42:
resId = R.drawable.ic_weather_42;
break;
case 43:
resId = R.drawable.ic_weather_43;
break;
case 44:
resId = R.drawable.ic_weather_44;
break;
case 45:
resId = R.drawable.ic_weather_45;
break;
case 46:
resId = R.drawable.ic_weather_46;
break;
case 47:
resId = R.drawable.ic_weather_47;
break;
default:
resId = R.drawable.ic_weather_3200;
break;
}
return resId;
}

[raincious]

能改个形式么？比如：

R.drawable里面加个方法get_ic_weather()。

if (code >= 3) {
resId = R.drawable.get_ic_weather(code);
} else {
resId = R.drawable.get_ic_weather(3200);
}

[batfree]

两种方法：
1. R里面的资源编号是有顺序的。找到第一个然后其他的依次+1
2. 反射，从字符串反射出R.drawable的对应的属性值。
第一个速度快，第二个保险。

[darktiny]

@raincious 不可以

[darktiny]

@batfree 不是很理解第二种方法要怎么实现

[hfcc8685]

表模式应该行

[zhangxiao]

R.drawable.ic_weather_N
这些必须这么命名么，如果是：R.drawable.ic_weather.N的形式会不会好点，可以有一个R.drawable.ic_weather._default

[expensivefreee]

用反射的方法最简单
下面是可以参考的代码
http://stackoverflow.com/questions/3545196/android-programatically-iterate-through-resource-ids

[qiibeta]

int resID = getResources().getIdentifier("ic_weather_"+String.valueOf(code), "drawable",getPackageName());
Drawable image = getResources().getDrawable(resID);

[darktiny]

@qiibeta 谢谢，非常有用

[darktiny]

@expensivefreee 顺便研究下，谢谢

[xpfd]

int ic_weathe[48] = {R.drawable.ic_weather_3200,R.drawable.ic_weather_3200,R.drawable.ic_weather_3200,R.drawable.ic_weather_3 .... 47};

if(code >= 0) && (code < 48){
return ic_weathe[code];
}else{
return R.drawable.ic_weather_3200;
}