受 django 启发，让枚举类 label 返回中文

[wuwukai007]

from enum import Enum

class XIntegerChoices(Enum):
    def __new__(cls, value, label):
        obj = object.__new__(cls)
        obj._value_ = value
        obj._label = label
        return obj

    def __eq__(self, other):
        if isinstance(other, int):
            return other == self.value
        if isinstance(other, XIntegerChoices):
            return other.value == self.value
        return False

    def __ne__(self, other):
        return not self.__eq__(other)

    def __lt__(self, other):
        if isinstance(other, int):
            return self.value < other
        if isinstance(other, XIntegerChoices):
            return self.value < other.value
        raise TypeError

    def __le__(self, other):
        return self.__eq__(other) or self.__lt__(other)

    def __gt__(self, other):
        if isinstance(other, int):
            return self.value > other
        if isinstance(other, XIntegerChoices):
            return self.value > other.value
        raise TypeError

    def __ge__(self, other):
        return self.__eq__(other) or self.__gt__(other)

    def __hash__(self):
        return hash(self.value)

    @property
    def value(self):
        return self._value_

    @property
    def label(self):
        return self._label

    @classmethod
    def members(self):
        return list(self)


class Action(XIntegerChoices):
    CREATED = (1, "创建")


if __name__ == '__main__':

    print(Action.CREATED == 2)
    print(Action.CREATED.label)
    print(Action.members())

# False
# 创建
# [<Action.CREATED: 1>]

[0x0208v0]

这个实现方式好棒！

[bthulu]

你就不能直接用中文枚举么? 用中文是会要了你的命, 还是丢了你的逼格?
print(Action.创建)

[wuwukai007]

@bthulu 如果是中英文+符号 混搭肯定不行，要考虑下代码健壮性，比如 应用商店(APP)

[gujigujij]

Enum 原生支持的

```

class CardTypeEnum(Enum):
ID_CARD = (1, '身份证')
TRAVEL_FOR_HK_MR = (2, '港澳居民来往内地通行证')
TRAVEL_FOR_TW = (3, '台湾居民来往大陆通行证')
PASSPORT = (4, '护照')

def __init__(self, code, text):
self.code = code
self.text = text


print(CardTypeEnum.ID_CARD.text )
```